Question

please solve step by step​

Answer 1

Answer:

x = 2, y = 1

Step-by-step explanation:

For Convenience

Let $p=x+y$.

And let $q=x-y$.

$\frac{3}{p} +\frac{2}{q} =3$ (p ≠ 0, q ≠ 0) → Multiply by pq.

$3q+2p=3pq$ --- *1

$\frac{2}{p} +\frac{3}{q} =\frac{11}{3}$ → Multiply by 3pq.

$6q+9p=11pq$ --- *2

By The Elimination Method

*1 × 11 - *2 × 3

$33q+22p=33pq$ ---*1 × 11

$18q+27p=33pq$ --- *2 × 3

$15q-5p=0$ --- *1 × 11 - *2 × 3

∴ $p=3q$ --- *3

Substitute *3 into *1.

$3q+6q=9q^2$

$q^2-q=0$

$q(q-1)=0$

∴ As q ≠ 0, q = 1. And hence p = 3.

$x+y=3$, $x-y=1$

∴ $x=2$ and $y=1$

Sorry xd I made some mistake at the last.

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