Question

please solve step by step and send me pic of answer....... my question is this ............the denominator of a rational number is greater than its numerator by 8 if the numerator is increased by 11 and the denominator is decreased by 1 the number oftained is 7 by 3.Find the rational number

Answer 1

ok it's same as my question

Answer 2

here is your answer
$let \: the \: rational \: number \: be \: \\ = \frac{x}{x + 8} \\ according \: to \: question \: if \\ \: numerator \: is \: increased \\ \: by \: 11 \: and \: denominator \: is \: \\ decreased \: by \: 1 \: \\ the \: new \: rationl \: number \: is \: \\ \frac{x + 11}{x + 8 - 1} = \frac{7}{3} \\ \frac{x + 11}{x + 7} = \frac{7}{3} \\ (x + 11) \times 3 = (x + 7) \times 7 \\ 3x + 33 = 7x + 49 \\ 33 = 7x + 49 - 3x \\ 33 = 4x + 49 \\ 33 - 49 = 4x \\ - 16 = 4x \\ x = \frac{ - 16}{4} = - 4$
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