please solve sum no 22 , I mark him as brianlist
Answers
1.1444444444...
(22)
Given 0.6(bar) + 0.47(bar). ----- (1)
(i)
Let x = 0.6 ----- (2)
= > x = 0.66...
Multiply both sides by 10, we get
= > 10x = 6.6 ----- (3)
On solving (2) & (3), we get
= > 10x - x = 6.6 - 0.6
= > 9x = 6
= > x = 6/9
= > x = 2/3.
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(ii)
Let x = 0.47. ---- (3)
= > x = 0.4777.
Multiply both sides by 10, we get
= > 10x = 4.777 ---- (4)
On solving (3) & (4), we get
= > 10x - x = 4.7777 - 0.4777
= > 9x = 4.3
= > x = 4.3/9
= > x = 43/90
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Now,
Substitute both in (1), we get
= > (2/3) + (43/90)
= > (60 + 43)/90
= > 103/90.
Therefore, the final answer is 103/90.
Hope this helps!