Question

please solve sum no 8

Answer 1

Let one number be x

other = x + 1

square of x = x²

square of x + 1 = (x+1)² = x² + 2x + 1

so,

x² + 2x + 1 - x² = 31

x² - x² + 2x + 1 = 31

2x + 1 = 31

2x = 31 - 1

2x = 30

$x = \frac{30}{2}$

x= 15

1st number = x = 15

2nd number = x + 1 = 15 + 1 = 16