Question

please solve the 1 ques​

Answer 1

Answer:

hence, answer is (c)x=2,x=-1

Answer 2

Answer:

The answer is - option (c)

Step-by-step explanation:

To find the solution of $x^{2}$ - x - 2 = 0

Follow the identity (x + a)(x + b) = $x^{2}$ + (a + b)x + ab to factorize the quadratic equation

= $x^{2}$ - x - 2

Now find the factors of the last term(-2) such that the factors add up to the middle term's constant(-1)

That is,

(-2) X 1 = -2[Last term]

-2 + 1 = -1[Middle term's constant]

CONTINUE

a = -2

b = 1

= $x^{2}$ - x - 2

= $x^{2}$ + (-2 + 1)x + (-2) X 1

= $x^{2}$ - 2x + x + (-2) X 1

Take common

= x(x - 2) + 1(x - 2)

Again take common

= (x + 1)(x - 2)[Factors of $x^{2}$ - x - 2]

Solutions of quadratic equation $x^{2}$ - x - 2 are -

Find the zeroes of the factors[(x + 1)(x - 2)]

x + 1 = 0

x = -1 (One of the solution of the quadratic equation given in the question)

And,

x - 2 = 0

x = 2 (One of the solution of the quadratic equation given in the question)