Please solve the 15th question . Please .
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15(i)---216a^3-2√2b^3 = (6a)^3-(2b)^3. So use a^3-b^3=(a-b) (a^2+b^2+ab) =. =(6a-2b) (36a^2+4b^2+12ab) (iii) 12x^2-17x+6== find factors of 12×6=72 in such a way their sum will be -17. =12x^2-9x-8x+6=3x(4x-3)-2(4x-3)=(4x-3)(3x-2). Ans. (4x-3)(3x-2)
sarrahtaherpatla:
Thank you so much
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