Question

Please. Solve the above question

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

Step-by-step explanation:

cotA = 1/tanA

cotB = 1/tanB

So cotA + cotB = 1/tanA + 1/tanB => $\frac{tanA + tanB}{tanA*tanB}$

Substituting this in the question we will get $\frac{tanA + tanB}{\frac{tanA +tanB}{tanAtanB} } = tanA*tanB$

Now tan = opp/adjacent

So if the side AC = x.

tanA = x/12 and tanB =12/x

so tanA*tanB = 1

Therefore, the ans = 1