Question

Please solve The above question fastly?

Answer 1

O is the midpoint .
extending BO to D and joining AD and DC.
∴ now abc is right angled Δ.so ∠b= 90
and ∠B + ∠D = 180 ( since ABCD is a ║gm)
similarly ∠A =∠B=∠C=∠D=90
now AD || BC and BA|| DC 
∴ ABCD is a rectangle.
BD and AC are diagonals.
∴ΔABC ≈ΔADC
            ___________________(ii)
allso
ΔBAD≈ΔBCD.
         ____________________(iii)
from (Ii) and (iii),
ΔABO≈ΔBOC
∴OA =OB=Oc.