Question

please solve the above question whose answer is{0,-1}

Answer 1

| x -1 | + y = 0
2x - y = 1

| x -1 | + y =0 is a modulus function so,
we break mod .

case 1:- x ≥ 1
x -1 + y =0

x +y = 1
2x -y = 1
solve both equations
x = 2/3 and y = 1/3

but x ≥ 1 so, no solution here

case 2 :- x < 1

-( x -1) + y =0
y -x + 1 = 0



x - y = 1
2x - y = 1
x = 0 and y = -1

x < 1 here x = 0 so, this is satisfied
now , x = 0 and y = -1
is the solution of this linear equations system .