please solve the above question with property
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AB ll CD
therefore,
AngleD = 75
then , z = 75( alternate interior angle)
Angle COD = 180-(75+35) = 180-110 = 80
angle COD = 80
angle COD = angle AOD
angle AOD = 80
y = 80 ( vertically opposits )
now ,
x = 180- ( 80+75)
x = 180- 155
x = 25
therefore,
AngleD = 75
then , z = 75( alternate interior angle)
Angle COD = 180-(75+35) = 180-110 = 80
angle COD = 80
angle COD = angle AOD
angle AOD = 80
y = 80 ( vertically opposits )
now ,
x = 180- ( 80+75)
x = 180- 155
x = 25
Raj2637:
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