Please solve the above two problems
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1.let angle pdq be x, then angle pdq =angle pef( corresponding angles)
similarly, angle pdc=angle pea
so aep+pef+feb= 180°(linear pair)
34°+x+74°=180°
x=72°
baki keh khud nikalle yaar
2. y+55°=180°( alternate interior angles(
y=135°
angle Bag + angle fga= 180° (cointerior angles)
angle fga =90°
z+55°=90°
z= 35°
similarly, angle pdc=angle pea
so aep+pef+feb= 180°(linear pair)
34°+x+74°=180°
x=72°
baki keh khud nikalle yaar
2. y+55°=180°( alternate interior angles(
y=135°
angle Bag + angle fga= 180° (cointerior angles)
angle fga =90°
z+55°=90°
z= 35°
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