Question

Please solve the attachment

Answer 1

${\boxed {\boxed {\boxed{ \underline{ \sf{See\:the\: Attachment }}}}}}$

Answer 2

hlw mate,

_____________

ur answer ,
==============

⬇️⬇️⬇️⬇️⬇️⬇️⬇️
L.H.S =tanA1−cotA+cotA1−tanA=tanA1−cotA+cotA1−tanA

=tanA1−1tanA+1tanA1−tanA=tanA1−1tanA+1tanA1−tanA

=tan2AtanA−1−1tanAtanA−1=tan2AtanA−1−1tanAtanA−1

=1tanA−1tan3A–1tanA=1tanA−1tan3A–1tanA

=1tanA−1(tanA−1)tan2A+tanA+1tanA=1tanA−1(tanA−1)tan2A+tanA+1tanA

=tan2A+tanA+1tanA=tan2A+tanA+1tanA

=tanA+1+1tanA=tanA+1+1tanA

=tanA+1+cotA=tanA+1+cotA

==R. H. S

hence proved...

any query or doubt then comment below...



mark me as BRAINLIEST and plz follow me too...