Question

For given semiconductor contribution of current due to electron and hole is in ratio 3/1 and the ratio of drift velocity for electron and hole is 5/2, then calculate the ratio of electron to hole concentration.

Answer 1

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Answer 2

Given :

Contribution of current due to electron and hole is in ratio 3/1 .

The ratio of drift velocity for electron and hole is 5/2 .

To Find :

The ratio of electron to hole concentration .

Solution :

We know , Current flow is given by :

$I=NAV_d$

Therefore , $N=\dfrac{I}{V_dA}$

So ,

$\dfrac{N_e}{N_n}=\dfrac{I_e}{I_n}\times \dfrac{V_{d_n}}{V_{d_e}}\\\\\dfrac{N_e}{N_n}=\dfrac{3}{1}\times \dfrac{2}{5}\\\\\dfrac{N_e}{N_n}=\dfrac{6}{5}$

Therefore , the ratio of electron to hole concentration is 6 : 5 .

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Semiconductors

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