Question

Please solve the below attachment of linear equation in one variable and co-ordinate geometry. Spam will be reported

46d37bb2557857f119a2b4186496e14a.pdf

Answer 1

Given :  Points  A ( 1 , 3)  , B ( - 1 , -1)   & C (-2  , - 3)

To find : Area of Triangle

Solution:

Answering 1st Question : ( post Question one by one)

Points  A ( 1 , 3)  , B ( - 1 , -1)   & C (-2  , - 3)  

Area of Triangle

= (1/2) |  1 (-1 -(-3))  - 1(-3 - 3)  - 2(3 -(-1)) )

= (1/2) |  2 + 6  - 8 |

= (1/2) |  0 |

= 0

Area of Figure   = 0  sq units

Points are Colinear

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