Please solve the below attachment of linear equation in one variable and co-ordinate geometry. Spam will be reported
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Given : Points A ( 1 , 3) , B ( - 1 , -1) & C (-2 , - 3)
To find : Area of Triangle
Solution:
Answering 1st Question : ( post Question one by one)
Points A ( 1 , 3) , B ( - 1 , -1) & C (-2 , - 3)
Area of Triangle
= (1/2) | 1 (-1 -(-3)) - 1(-3 - 3) - 2(3 -(-1)) )
= (1/2) | 2 + 6 - 8 |
= (1/2) | 0 |
= 0
Area of Figure = 0 sq units
Points are Colinear
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