Question

please
solve the equation
1/x-2 + 1/x-3 +1/x-4 =0​

Answer 1

(x-3)(x-4)+(x-2)(x-4)+(x-2)(x-3)=0

x2-3x-4x+12+x2-2x-4x+8+x2-2x-3x+6=0

3x2-18x+26=0

x value can be find by quardiratic formula

(x= -b+√b2-4ac/2a,-b-√b2-4ac/2a

x= 18+√324-312/6,18-√324-312/6

=18+√12/6,18-√12/6

=2×9+2√3/6,2×9-2√3/6

=9+√3/3,9-√3/3