please solve the equation ......?
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Let the digit in the ten's place be T and one's place be O respectively
T=3(O)
the number is 3(0)x10+(0)
After reversing digits, the number would be (0)x10+3(0)
Sum is then 40(0) + 4(O) = 4(O)x(10+1) = 4(O)x 11 = 88
therefore O = 88/(11x4) = 2
and T = 3x2 = 6
The number is 62
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