Question

Please solve the fourth question
The first answerer will be marked brainiest

Answer 1

Let the digit at tens place be x and the digit at units place be y.

Therefore the decimal expansion is 10x + y.   ------ (*)

Given that A two-digit number is 3 more than 4 times the sum of its digits.

= > 10x + y = 4(x + y) + 3

= > 10x + y = 4x + 4y + 3

= > 10x + y - 4x - 4x = 3

= > 6x - 3y = 3

= > 2x - y = 1  ------ (1)


Given that if 18 is added to the number, its digits are reversed.

= > 10x + y + 18 = 10y + x

= > 10y + x - 10x - y = 18

= > 9x - 9y = -18 

= > x - y = -2 ------- (2)


On solving (1) & (2), we get

2x - y = 1

x - y = -2

-----------------

x = 3

Substitute x = 3 in (1), we get

= > x - y = -2

= > 3 - y = -2

= > -y = -2 - 3

= > y = 5.

Substitute x = 3 and y = 5 in (*), we get

= > 10x + y

= > 10(3) + 5

= > 35.


Therefore the original number = 35.


Hope this helps!

Answer 2

I hope you got your answer