Please solve the given Question.
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1st Method:
Let the cost price of A = 100.
Given that A sells a computer to B at a profit of 10%.
Then the Cost price of B = 100 + 10% of 100
= 100 + 10/100 * 100
= 110.
Given that B sells it to C at a profit of 15%.
Cost price of C = 110 + 15% of 110
= 110 + 15/100 * 110
= 126.5.
Given that cost price of C = 35200.
Now,
126.5 = 35200
1 = 35200/126.5
100 = 35200 * 100/126.5
= 27826.
Therefore the cost price of A = ~27826.
2nd Method:
115% of 110% of A = 35200
115/100 * 110/100 * A = 35200
253A/200= 35200
253A = 35200 * 200
253A = 7040000
A = 7040000/253
A = ~27826.
Hope this helps!
Let the cost price of A = 100.
Given that A sells a computer to B at a profit of 10%.
Then the Cost price of B = 100 + 10% of 100
= 100 + 10/100 * 100
= 110.
Given that B sells it to C at a profit of 15%.
Cost price of C = 110 + 15% of 110
= 110 + 15/100 * 110
= 126.5.
Given that cost price of C = 35200.
Now,
126.5 = 35200
1 = 35200/126.5
100 = 35200 * 100/126.5
= 27826.
Therefore the cost price of A = ~27826.
2nd Method:
115% of 110% of A = 35200
115/100 * 110/100 * A = 35200
253A/200= 35200
253A = 35200 * 200
253A = 7040000
A = 7040000/253
A = ~27826.
Hope this helps!
RehanAhmadXLX:
welcome
Answered by
9
Hello friend....
Here is your solution...
Option " D" is the correct one....
Thank you so much.....
Here is your solution...
Option " D" is the correct one....
Thank you so much.....
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