Question

please solve the no 2​

Answer 1

Step-by-step explanation:

Since the figure is divided into one trapezium AEDC & one triangle ABC

Therefore we have to find the area of the two polygons separately and then add the both to get the answer

In AEDC,

Height = 2cm

Length of the parallel sides = 12 cm(a) & 8 cm (b)

Area = 1/2 * height*( a+b)

=1/2*2 cm*(12cm+8cm)

=1/2 *2cm*20cm

=20sq. cm

Again,

In ABC,

Height=4cm

Base= 12 cm

Area = 1/2 * base* height

=1/2*12cm*4cm

=1/2*48sq.cm

=24 sq. cm

Total area of ABCDE

= 20 +24 sq. cm

= 44sq. cm

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Answer 2

Step-by-step explanation:

iii

Area of given quadrilateral

= ar. of ABC + ar. of trapezium ACDE

$= \frac{1}{2} \times base \times height + \frac{sum \: of \: parallel \: side}{2} \times height \\ = \frac{1}{2} \times 12cm \times 4cm + \frac{12cm + 8cm}{2} \times 2cm \\ = 6cm \times 4cm + \frac{20cm}{2} \times 2cm \\ = 24 {cm}^{2} + 10cm \times 2cm \\ = 24 {cm}^{2} + 20 {cm}^{2} \\ = 44 {cm}^{2}$