Question

Please solve the problem ​

Answer 1

Answer:

I hope this answer is help you dear friend

Answer 2

☯GIVEN :

• Divide the sum of $\bf{ \dfrac{13}{5}}$ and $\bf{ \dfrac{-12}{7}}$ by the product of $\bf{ \dfrac{-31}{7}}$ and $\bf{ \dfrac{1}{-2}}$.

➲SOLUTION :

Sum of $\bf{ \dfrac{13}{5}}$ and $\bf{ \dfrac{-12}{7}}$ :

$\implies{ \sf{\dfrac{13}{5} +\dfrac{-12}{7} }}$

$\implies{ \sf{\dfrac{91 + ( - 60)}{35} }}$

$\implies{ \sf{\dfrac{91 - 60}{35} }}$

$\implies{ \green {\bf{\dfrac{31 }{35} }}}$

Product of $\bf{ \dfrac{-31}{7}}$ and $\bf{ \dfrac{1}{-2}}$ :

$\implies{ \sf {\dfrac{ - 31}{7} \times \dfrac{1}{ - 2} }}$

$\implies{ \sf {\dfrac{ \cancel{ - }31}{ \cancel{-} 14} }}$

$\implies{ \green {\bf{\dfrac{31 }{14} }}}$

Dividing the sum of $\bf{ \dfrac{13}{5}}$ and $\bf{ \dfrac{-12}{7}}$ by the product of $\bf{ \dfrac{-31}{7}}$ and $\bf{ \dfrac{1}{-2}}$ :

$\implies{ \sf{ Sum \div Product }}$

$\implies{ \sf{ \dfrac{31}{35} \div\dfrac{31}{14} }}$

$\implies{ \sf{ \dfrac{ \cancel{31}}{ \cancel{35}} \times \dfrac{ \cancel{14}}{ \cancel{ \cancel{31}}} }}$

$\implies{ \huge{\boxed {\red {\bf{\dfrac{2 }{5}} }}}}$