Question

please solve the problem.​

Answer 1

$\frac{16}{9} \times \frac{ \sin(50) }{ \cos(40) } - \frac{7}{9} \times \frac{ \cos(63) \times \csc(27) }{ \tan(15) \tan(35) \tan(55) \tan(75) }$

$converting \: into \: (theta - 90)$

$we \: obtain = \frac{16}{9} \times \frac{1}{1} - \frac{7}{9} \times \frac{1}{1}$

$so \: by \: solving = \\ \frac{16 - 7}{9} = \frac{9}{9} = 1$
PLEASE MARK ME AS BRAINLIEST