PLEASE solve the problem fast
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tan(A-B)=(tanA-tanB)/(1+tanAtanB)
or,tan45°=√3/(1+tanAtanB)
or,1=√3/(1+tanAtanB)
or,(1+tanAtanB)=√3
or,tanAtanB=√3-1 Ans
Hope it Helps.
or,tan45°=√3/(1+tanAtanB)
or,1=√3/(1+tanAtanB)
or,(1+tanAtanB)=√3
or,tanAtanB=√3-1 Ans
Hope it Helps.
Urvish19:
thanks
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