Question

Please solve the problem given in the image

Answer 1

Here is ur answer.......

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Answer 2

Answer:

tan∅/tanФ = 1/2

Step-by-step explanation:

GIven:

In tri. ACD , ∠ACD = 90° and ∠ADC = Ф

In tri. ACB  , ∠ACB = 90° and ∠ABC = ∅

D is the midpoint of BC.

∴ CD=BD=1/2BC or 2CD=2BD=BC

In tri. ACD

tanФ= AC/CD .........(1)

In tri. ACB

tan∅= AC/BC

it can be also written as

tan∅= AC/2CD .............(2)

dividing 1 and 2

tan∅/tanФ = AC/2CD/AC/CD

                 = AC/2CD×CD/AC

tan∅/tanФ = 1/2

Hence proved

Hope this wil help u .......

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