Please solve the problem given in the image
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Here is ur answer.......
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Answer:
tan∅/tanФ = 1/2
Step-by-step explanation:
GIven:
In tri. ACD , ∠ACD = 90° and ∠ADC = Ф
In tri. ACB , ∠ACB = 90° and ∠ABC = ∅
D is the midpoint of BC.
∴ CD=BD=1/2BC or 2CD=2BD=BC
In tri. ACD
tanФ= AC/CD .........(1)
In tri. ACB
tan∅= AC/BC
it can be also written as
tan∅= AC/2CD .............(2)
dividing 1 and 2
tan∅/tanФ = AC/2CD/AC/CD
= AC/2CD×CD/AC
tan∅/tanФ = 1/2
Hence proved
Hope this wil help u .......
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