please solve the problem in picture Q-3and4
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3) Diameter of the wheel = 28 cm
Radius = 28/2 =14cm
Circumference = 2πr = 2 x 22/7 x 14 = 88cm
Total distance = 11km = 1100000cm
number of revolutions = 1100000/88 = 12500
4) Diameter of the equator = 12530 km
Radius = 12530/2 = 6265 km
Circumference = 2πr= 2 x22/7 x 6265
= 39380 km
Radius = 28/2 =14cm
Circumference = 2πr = 2 x 22/7 x 14 = 88cm
Total distance = 11km = 1100000cm
number of revolutions = 1100000/88 = 12500
4) Diameter of the equator = 12530 km
Radius = 12530/2 = 6265 km
Circumference = 2πr= 2 x22/7 x 6265
= 39380 km
Anonymous:
Hey recheck ur first answer I think it's 12500
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I hope help you attached answer
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