Question

please solve the problem of linear equation

Answer 1

ans 9=
let the fixed charge be Rs x and charge paid for each additional km be Rs y
ATQ
x +2y=170 ----(1)
x+30y=250------(2)
subtracting equation (1) from eq (2)
x+30y=250
x+2y=170
- - -
-----------------
28y=80
y =80/28
y=2.85
putting value of y in eq 1 we get
x+2y=170
x+2(2.85)=170
x+5.71=170
X=170-5.71
x =164.29
now charge for traveling 70 km is
x +70y
164.29+70(2.85)
Rs 361