Please solve the Qno. 5 in the attachment
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Answered by
4
✨here is your answer.✨
we know that the ratio of sides of similar triangles are equal so,
by thales theorm - AD/DB= AE/EC
=. 6/9 = 8/12
2/3 = 2/3
SO, WE , CAN SE TRIANGLE ADE IS SIMILAR TO TRIANGLE ABC.
SO, DE // BC
SO, WE CAN SAY angle ADE = ABC = 48°
✌️HOPE IT HELPS U ✌️
HAVE A NICE DAY
we know that the ratio of sides of similar triangles are equal so,
by thales theorm - AD/DB= AE/EC
=. 6/9 = 8/12
2/3 = 2/3
SO, WE , CAN SE TRIANGLE ADE IS SIMILAR TO TRIANGLE ABC.
SO, DE // BC
SO, WE CAN SAY angle ADE = ABC = 48°
✌️HOPE IT HELPS U ✌️
HAVE A NICE DAY
Answered by
5
AD/AB = 6/6+9 = 6/15 = 2/5
AE/AC = 8/ AE+ EC = 8/8+12 = 8/20 = 2/5
so ADE IS SIMILAR TO ABC
SO DE BECOMES PARALLEL TO BC
AS DE AND BC are parallel
therefore ABC = 48( corresponding angle)
Hope it will help u
AE/AC = 8/ AE+ EC = 8/8+12 = 8/20 = 2/5
so ADE IS SIMILAR TO ABC
SO DE BECOMES PARALLEL TO BC
AS DE AND BC are parallel
therefore ABC = 48( corresponding angle)
Hope it will help u
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