Question

please solve the question​

Answer 1

Answer:

a=31/4

d=19/2-31/4=7/4

a99=a+98d=31/4+98*7/4=7.75+177.5=185.25

Step-by-step explanation:

Answer 2

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The A.P. series is given by

$\rightarrow7 \frac{3}{4} ,9 \frac{1}{2} ,11 \frac{1}{4} \\ \rightarrow \frac{31}{4} , \frac{19}{2} , \frac{45}{4}$

Now the difference is ,,

$\rightarrow \: d = \frac{19}{2} - \frac{31}{4} \\ \rightarrow \boxed{ d = \frac{7}{4} }$

first term is,,

$\rightarrow \boxed{a = \frac{31}{4} }$

now we have the formula of n'th term is..

$\implies \boxed{a_n = a + (n - 1)d}$

therefore the 99'th term is .....

$\implies \boxed{a_{99 }= a+ (99 - 1)d} \\ \implies \boxed{a_{99 }= \frac{31}{4} + 98 \times \frac{7}{4} } \\ \implies \boxed{a_{99 }= \frac{31 +686 }{4} = \frac{717}{4} }$

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