Question

Please solve the question 15

Answer 1

In ∆ABL.
<BAL + <ABL +<ALB = 180° (angle sum property of triangle).
<ALB = 90°.
<BAL + <ABL + 90° = 180°.
<BAL + <ABL = 90°.
<BAL + <ABC = 90° (either ABL or ABC one and the same thing)--------1
In ∆ABC
<BAC + <ABC + <BCA = 180° (angle sum property of triangle).
<BAC = 90°.
90° + <ABC + <BCA = 180°.
<ABC + <BCA = 90°---------2
Equating 1 and 2.
<BAL + <ABC = <ABC + <BCA
Cancelling <ABC from both sides.
We get:
<BAL = <BCA.
Hence proved.
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