please solve the question..
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1
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Let one zero be t other be
t
1
Product = t×
t
1
=1
we know that for ax
2
+bx+c=0 the product of roots=
a
c
Here t,
t
1
are the roots of p(x)=(k+4)x
2
+13x+3k=0
a=k+4,b=13,c=3k
Product of roots =
a
c
=
k+4
3k
=1
3k=k+4
2k=4
∴
k=2
Answered by
1
Answer:
The value of k is 2...
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