Question

please solve the question​

Answer 1

Step-by-step explanation:

$\int \frac{dx}{ \sqrt{2ax - {x}^{2} } } = {a}^{n} \sin^ {- 1} ( \frac{x}{a} - 1)$

$= > \int \frac{dx}{ \sqrt{ {a}^{2} - {(x - a)}^{2} } } = {a}^{n} \sin^{ - 1} ( \frac{x}{a} - 1 )$

$= > \sin^{ - 1} ( \frac{x - a}{a} ) = {a}^{ n} \sin^{ - 1} ( \frac{x}{a} - 1 )$

$= > n = 0$