Question

please solve the Question

Answer 1

Let the total marks be a
In first case
Passing marks = 20% of a +10
= a/5 + 10
= a+50/5---------(1)

Now,
In second case
Passing marks = 42 - 12% of a
= 42 - 12a/100
= 42 - 3a/25
= 1050 - 3a/25------------(2)

From equation 1 and 2, we get

a+50/5 = 1050 - 3a/25
a+50 = 1050 - 3a/5
5a+ 250 = 1050 - 3a
8a = 800
a= 100

Maximum marks = 100

Hope it help you

Please mark as brainliest if you liked the solution