Math, asked by kunalyadav1306, 1 day ago

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Answered by rfetherman2022
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In the given parallelogram ABCD DP = BQ and ∠ADP=∠CBQ T

In the given parallelogram ABCD DP = BQ and ∠ADP=∠CBQ T

In the given parallelogram ABCD, DP = BQ and ∠ADP and =∠CBQ

. To which triangle is ΔADP congruent to?

A.ΔCBQ

B.ΔPDQ

C.ΔQBC

D.ΔPQB

Please scroll down to see the correct answer and solution.

Right Answer is: A

SOLUTION

In

ΔADP and ΔCBQ

∠ADP=∠CBQ

(given) AD = BC  

opposite sides of parallelogram are equal)

DP = QB   (given)

ΔADP≅ΔCBQ.

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