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In the given parallelogram ABCD DP = BQ and ∠ADP=∠CBQ T
In the given parallelogram ABCD DP = BQ and ∠ADP=∠CBQ T
In the given parallelogram ABCD, DP = BQ and ∠ADP and =∠CBQ
. To which triangle is ΔADP congruent to?
A.ΔCBQ
B.ΔPDQ
C.ΔQBC
D.ΔPQB
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Right Answer is: A
SOLUTION
In
ΔADP and ΔCBQ
∠ADP=∠CBQ
(given) AD = BC
opposite sides of parallelogram are equal)
DP = QB (given)
ΔADP≅ΔCBQ.
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