please solve the question
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Hope it will help you
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Sandhyagupta54:
thanks a lot
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hey here is ur answer
let the common multiple for both the sides be x
the area of trapezium =1/2(a+b)h
385=1/2(4x+7x)14
385*2/14=11x
385*2/14*11=x
x=35/7
x=5
sides are 5(4)and 7(5)
=20 and 35 cm
I hope this helps you
let the common multiple for both the sides be x
the area of trapezium =1/2(a+b)h
385=1/2(4x+7x)14
385*2/14=11x
385*2/14*11=x
x=35/7
x=5
sides are 5(4)and 7(5)
=20 and 35 cm
I hope this helps you
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