Question

please solve the question

Answer 1

hope it helped .........

Answer 2

$given \\ \\ x + 2y = 8 \\ \\ xy = 2 \\ \\ \\ \\ to \: find \\ \\ x {}^{2} + 4y {}^{2} \\ \\ \\ \\ \\ \\ here \\ \\( x + 2y) {}^{2} = x {}^{2} + 2 \times x \times 2y + (2y) {}^{2} \\ \\ = > (8) {}^{2} = x {}^{2} + 4xy + 4y {}^{2} \\ \\ = > 64 = x {}^{2} + 4 \times 2 + 4y {}^{2} \\ \\ = > 64 = x {}^{2} + 8 + 4y {}^{2} \\ \\ = > x{}^{2} + 4y {}^{2} = 64 - 8 \\ \\ = > x {}^{2} + 4y {}^{2} = 56$