Question

please solve the question

Answer 1

Answer:

Step-by-step explanation:they are in A.P

2log(2^x-1)=log(2^x-1)+log2

Log(2^x-1)^2=log{2(2^x+3)}

(2^x-1)^2=2(2^x+3)

2^(2x)-2(2^x)+1=2(2^x)+6

Let 2^x =t

t^2-4t-5=0

(t-5)(t+1)=0

t=5;t=-1

2^x=5;2^x=-1

x=log2^5 and x=log2^(-1)

Therefore x=log2^5 and it is 4th option