Question

Please solve the question​

Answer 1

$heya \\ \\ \\ some \: formula \: \: \: \\ \\ (1 + \tan {}^{2} ( \alpha ) ) = \sec {}^{2} ( \alpha ) \\ \\ and \: \\ \\ \\ 1 - \sin {}^{2} ( \alpha ) = \cos {}^{2} ( \alpha ) \\ \\ \\ \\ l.h.s \\ \\ \\ ( \sec {}^{2} ( \alpha ) ) \times (1 {}^{2} - \sin {}^{2} ( \alpha ) ) \\ \\ \\ = > \\ \\ ( \sec {}^{2} ( \alpha ) ) \times ( \cos {}^{2} ( \alpha ) ) \\ \\ \\ \\ = > ( \cos {}^{2} ( \alpha ) \div \cos {}^{2} ( \alpha ) ) \\ \\ \\ = 1$

Answer 2

I hope this is correct and if it helped you please mark it brainliest