please solve the question and give explanation also
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This is answer of 17th question
Q-16
Let assume actual speed =x
Speed=distance /time
5x/7=42/1.68 <=((1+(40/60)+(48/3600)=1.68)
5x/7=25
X=25x7/5
X=35KM/H
17 question explanation
Let assume total work 60
(I.e. LCM of 20 and 15)
Then i calculate working ability of a and b of 1 day
(A's efficiency =3unit of work every day
And B's efficiency =4 unit of work)
So in one day a and b work together will complete unit of work =3+4=7
In 4 days =7x4=28
Remaining work =60-28=32
The fraction of remaining work= 32/60
=8/15
Q-16
Let assume actual speed =x
Speed=distance /time
5x/7=42/1.68 <=((1+(40/60)+(48/3600)=1.68)
5x/7=25
X=25x7/5
X=35KM/H
17 question explanation
Let assume total work 60
(I.e. LCM of 20 and 15)
Then i calculate working ability of a and b of 1 day
(A's efficiency =3unit of work every day
And B's efficiency =4 unit of work)
So in one day a and b work together will complete unit of work =3+4=7
In 4 days =7x4=28
Remaining work =60-28=32
The fraction of remaining work= 32/60
=8/15
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avi106:
I don't.understand
actually this is the shortcut method
wait I will explain u
check it now
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