Question

Please solve the question given above..

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Answer 1

Answer:

angle ABL. 30°

angle CBL. 60°

angle BCA. 30°

Step-by-step explanation:

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Answer 2

Answer:

To find angles.

Given ::

A right angle

• <A = 60°
• <BLC = 90° ( perpendicular )
• <ABC = 90 ( Given right angle )

Unknown angles ::

<BCA =?

<CBL = ?

<ABL = ?

Let's do ::

In ∆ABL ,

• <A = 60° ( Given )
• <L = 90° ( Given, Perpendicular drawn)
• <B = ?

< B = 180 - (90+60)

=. 180 - 150

= 30°

<B = 30°

<ABL = 30°

because of angle sum Property. ( the sum of angles of a triangle is 180° )

Now , let's find the angle <CBL

we know that <B = 90° because of right angle then,

<CBL = 90° - <ABL ( we find this above )

= 90 - 30

= 60°

<CBL = 60°

Now, let's find the angle <BCA

Consider the ∆BCL

• <L = 90° ( perpendicular drawn, given)
• <B = 60°
• <C = ?

<C = 180 - (90+60)

= 180 - 150

= 30

<C = 30°

<BCA = 30°

because of Angle Sum Property.

a) <BCA = 30°

b) <CBL = 60°

c) <ABL = 30°

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