please solve the question given in image
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Draw BL⊥PQ and CM⊥RS. As PQ∥RS, so, BL∥CM.
The alternate interior angles are equal, so,
∠LBC=∠MCB (1)
It is known that the angle of reflection is equal to the angle of incidence, therefore,
∠ABL=∠LBC (2)
And,
∠MCB=∠MCD (3)
From equation (1), (2) and (3),
∠ABL=∠MCD (4)
Add equation (1) and (4),
∠LBC+∠ABL=∠MCB+∠MCD
∠ABC=∠BCD
Since, these are the interior angles and are equal, hence, AB∥CD.
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