Please solve the question. I want to know if I am right or not.
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Answer:
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1
Answer:
Weight(in gms) No. of Packets
200−201 12
201−202 26
202−203 20
203−204 9
204−205 2
205−206 1
Here the maximum frequency f
m
=26
The corresponding class 201−202 is the modal class.
L=201,f
m
=26,f
1
=12,f
2
=20,h=1
Mode =L+(
2f
m
−f
1
−f
2
f
m
−f
1
)h
=201+(
2×26−12−20
26−12
)1
=201+(
20
14
)
=201+
10
7
=201.7
Modal weight of the coffee is 201.7 gms.
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