Question

please solve the question immediately​

Answer 1

Answer:

but i dont know how to mark as brainlist

Answer 2

hope it helps u ✌

Moles of Cu=

63.5

0.4

=6.3×10

−3

mol

Faraday used =2×6.3×10

−3

=12.6×10

−3

mol

Now for oxygen,

2H

2

O⟶O

2

+4H

+

+4e

−

Hence, 4 mol e

−

⟶22400 cm

3

of O

2

.

12.6×10

−3

⟶

2

22400

×12.6×10

−3

cm

3

of O

2

=141 cm

3