please solve the question in the attachment
Q.5 and Q. 6
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Q.No.5:
solution:
Given:
∆PQR is an isosceles triangle, where
PQ=PR,
PS=PT
To Prove:QT=RS
Proof:
In ∆PQT and ∆PRS,
PQ=PR(because PQ=PR,Given)
angle QPR=angle RPQ(common angle)
PS=PT(given)
Therefore ∆PQT is congruent to ∆PRS.
Therefore,
RS=TQ(by CPCT)
Now in ∆QRS and ∆QRT,
QR=QR(common base)
RS=TQ(Proved)
QS=TR(because PQ=PR, given)
Therfore ∆QRS is congruent to ∆QRT.
Therefore,
QR=RS(by CPCT)
Hence proved.
Thank you.
solution:
Given:
∆PQR is an isosceles triangle, where
PQ=PR,
PS=PT
To Prove:QT=RS
Proof:
In ∆PQT and ∆PRS,
PQ=PR(because PQ=PR,Given)
angle QPR=angle RPQ(common angle)
PS=PT(given)
Therefore ∆PQT is congruent to ∆PRS.
Therefore,
RS=TQ(by CPCT)
Now in ∆QRS and ∆QRT,
QR=QR(common base)
RS=TQ(Proved)
QS=TR(because PQ=PR, given)
Therfore ∆QRS is congruent to ∆QRT.
Therefore,
QR=RS(by CPCT)
Hence proved.
Thank you.
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answer and procedures is in attachment
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