please solve the question in the attachment
Q. 6
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since angles opposite to equal sides are equal. So, Angle D = Angle E.
In s ACD and ABE,
Angle D = Angle E (proved earlier)
AD = AE (using hint)
Angle A = Angle A (common)
So, ACD congruent to ABE
So, BE = CD (by cpct)
In s ACD and ABE,
Angle D = Angle E (proved earlier)
AD = AE (using hint)
Angle A = Angle A (common)
So, ACD congruent to ABE
So, BE = CD (by cpct)
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