Question

please solve the question in the image​

Answer 1

$\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$

$y = \frac{9}{4}$

Solution :-

$\frac{y - 6}{4} = \frac{2y}{5} - \frac{7(y + 3)}{20}$

$\frac{y - 6}{4} = \frac{20(2y) - 5(7(y + 3))}{5 \times 20}$

$\frac{y - 6}{4} = \frac{40y - 35(y + 3)}{100}$

$\frac{y - 6}{4} = \frac{40y - 35y - 105}{100}$

$\frac{y - 6}{4} = \frac{5y - 105}{100}$

Now took the denominators of both LHS and RHS to thier opposite sides,

$100(y - 6) = 4(5y - 105)$

$100y - 600 = 20y - 420$

$100y - 20y = 600 - 420$

$80y = 180$

$y = \frac{180}{80}$

$y = \frac{9}{4}$

Verification :-

$\frac{y - 6}{4} = \frac{2y}{5} - \frac{7(y + 3)}{20}$

Now substitute the value of y in the terms of y

$( \frac{ (\frac{9}{4} )- 6 }{4} ) = ( \frac{2( \frac{9}{4}) }{5} ) - ( \frac{7( \frac{9}{4})}{20} )$

$\frac{ \frac{9 - 24}{4} }{4} = \frac{( \frac{8}{4}) }{5} - \frac{7( \frac{9 + 12}{4}) }{20}$

$\frac{ - 15}{16} = \frac{18}{20} - ( \frac{7( \frac{21}{4}) }{20} )$

$\frac{ - 15}{16} = ( \frac{18}{20} ) - ( \frac{ \frac{147}{4} }{20} )$

$\frac{ - 15}{16} = ( \frac{18}{20} ) \times ( \frac{4}{4}) - ( \frac{147}{80} ) \\ \frac{ - 15}{16} = \frac{72}{80} - \frac{147}{80}$

$\frac{ - 15}{16} = \frac{72 - 147}{80}$

$\frac{ - 15}{16} = \frac{ - 75}{80}$

$\frac{ - 15}{16} = \frac{ - 15}{16}$

Hence Verified

Answer 2

Answer:

(y-6)/4 = 2y/5 - 7(y+3)/20

yo there's a mistake, it's -21 not +21 just make sure of the mistake

and

y= -15/4