Please solve the question its urgent for exam
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khanujarashmit:
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Answered by
1
1) Rationalize the denominator:
3+2√3−2√(3+2√3+2√)3+23−2(3+23+2)
9+32√+32√+232−2√2
2 Simplify
9+32√+32√+29+32+32+2 to 9+62√+29+62+2
9+62√+232−2√2
3 Simplify
9+62√+29+62+2 to 11+62√11+62
11+62√32−2√2
Simplify 3232 to 99
11+62√9−2√2
11+62√9−2
Simplify 9−29−2 to 77
11+62√7
So a = 11/7
b = 6/7
3+2√3−2√(3+2√3+2√)3+23−2(3+23+2)
9+32√+32√+232−2√2
2 Simplify
9+32√+32√+29+32+32+2 to 9+62√+29+62+2
9+62√+232−2√2
3 Simplify
9+62√+29+62+2 to 11+62√11+62
11+62√32−2√2
Simplify 3232 to 99
11+62√9−2√2
11+62√9−2
Simplify 9−29−2 to 77
11+62√7
So a = 11/7
b = 6/7
Answered by
2
Corrected solution is attached below
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