Question

Please Solve the question l will mark you as a brainliest

Answer 1

Answer:

Terminating Decimal Expansion

Step-by-step explanation:

$\dfrac{441}{2^2 \times 5^7 \times 7^2} = \dfrac{3^2 \times 7^2}{2^2 \times 5^7 \times 7^2}$

$\dfrac{441}{2^2 \times 5^7 \times 7^2} = \dfrac{3^2}{2^2 \times 5^7}$

$\dfrac{441}{2^2 \times 5^7 \times 7^2} = \dfrac{9}{312500}$

$\dfrac{441}{2^2 \times 5^7 \times 7^2} = \0.0000288$

Answer: It is a terminating decimal expansion.

Answer 2

Answer:

A terminating decimal.

Step-by-step explanation:

441/( 2² · $5^{7}$ · 7² )

= ( 3² · 7² )/( 2² · 5^7 · 7² )

After cancellation , we get

= ( 3² )/( 2² · 5^7 )

[ Terminating decimal ]

∵ denominator is of the form 2^n × 5^m

Verification :

3²/( 2² · 5^7 )

= ( 3² · 2^5 )/( 2² · 2^5 · 5^7 )

= ( 9 × 32 )/( 2 × 5 )^7

= 288/( 10 )^7

= 0.0000288 ( terminating decimal )

....