Question

find the simple interest and amount when principal 450rs rate of interest per annum 9/2% and 3 years 4month

Answer 1

Here, Principal=450Rs,Rate=9/2%and Time3+4/12years=10/3
SI=P×R×T/100=
=[(450×9×10)/100×2×3]Rs
=135/2Rs
=67.5Rs
Amount =Principal+SI
=(450+67.5)
=517.5

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=517.5\:rupees}}}$

$\green{\therefore{\text{Amount=9684\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 3\:years\:4\:months} \\ \\ : \implies \text{Principal(p) = 450\:rupees} \\ \\ : \implies \text{Rate(r) = 4.5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\\\\ :\implies \text{Amount=?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{450 \times 4.5\times\frac{40}{12}}{100} \\ \\ : \implies S.I = \frac{45 \times18}{12} \\ \\ \green{ : \implies \text{S.I= 67.5\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =67.5\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{Amount=67.5+450=517.5\:rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$