Math, asked by sarthaksarkar31, 11 months ago

Please Solve the question no. 2 & 3...​

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Answered by Anonymous
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Answer:

2) 8 cows

3) Cost price of the chair was Rs. 33.75.

Step-by-step explanation:

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2)  Let s, g, c be the cost of 1 sheep, 1 goat, 1 cow respectively.

"the cost of 5 sheep is equal to the cost of 8 goats"

=>  5s = 8g

"the cost of 30 goats is equal to the cost of 3 cows"

=> 30g = 3c  =>  10g = c

So...

50s = 10 × (5s) = 10 × (8g) = 80g = 8 × (10g) = 8c

That is, the cost of 50 sheep is equal to the cost of 8 cows.

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3)

Let t be the cost of the table and c the cost of the chair.

Since the table was sold for a 12% profit, its selling price was 1.12t.

Since the chair was sold for a 4% loss, its selling price was 0.96c.

Together, the cost was t+c=90, so t = 90 - c.

Also, there was a 6% profit so the total selling price was 1.06×90 = 95.4.

Therefore

total selling price = selling price of table + selling price of chair

=> 95.4 = 1.12t + 0.96c

=> 95.4 = 1.12(90 - c) + 0.96c

=> 95.4 = 1.12×90 - 1.12c + 0.96c

=> 1.12c - 0.96c = 100.8 - 95.4

=> 0.16c = 5.4

=> c = 5.4 / 0.16 = 33.75

So the cost price of the chair was Rs. 33.75.

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