please solve the question number 18... brainliest question...chance available
10 points
Attachments:
Answers
Answered by
1
IN ABC and ΔAPQ
∠BAC=∠PAQ(COMMON)
∠ABC=∠APQ(CORRESPONDING ANGLES)
BY A.A Axiom
ΔABC≈ΔAPQ
BC/PQ=AC/AQ=AB/AP
BC=AB/AP*PQ
=12/4*5
=3*5
=15
∠BAC=∠PAQ(COMMON)
∠ABC=∠APQ(CORRESPONDING ANGLES)
BY A.A Axiom
ΔABC≈ΔAPQ
BC/PQ=AC/AQ=AB/AP
BC=AB/AP*PQ
=12/4*5
=3*5
=15
Attachments:
Mohit0007:
thanj you so much
Similar questions