please solve the question number 19 complete solution and send the pic of this solution A and B both parts solve
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Angle SOR=angle QOR (each 90)
QR=SR (in rhombus all sides are equal)
OR=OR (common)
Therefore triangle QOR=SOR (SAS)
Angle QRO =SRO by (cpct)
QR=SR (in rhombus all sides are equal)
OR=OR (common)
Therefore triangle QOR=SOR (SAS)
Angle QRO =SRO by (cpct)
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